Doppelte Elemente aus Dictionary mit listen als Value aussortieren

[Fire Spike]

Hallo ich habe mir per Zufall ein Dictionary mit einem Zeichen als Schlüssel und zufälligen RGB Werten generieren lassen.
Wie kann ich jetzt am einfachsten schauen ob ein RGB Wert doppelt vorkommt?
Ich hatte die Idee die Listen in ein Set zu packen, aber das geht ja nicht
Das ist das Dictionary:

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{"a": [86, 210, 158], "b": [37, 140, 23], "c": [138, 16, 211], "d": [199, 36, 16], "e": [168, 40, 196], "f": [114, 237, 186], "g": [94, 146, 147], "h": [242, 87, 253], "i": [52, 9, 192], "j": [176, 23, 93], "k": [217, 248, 144], "l": [162, 111, 83], "m": [130, 186, 166], "n": [241, 88, 254], "o": [139, 58, 216], "p": [243, 80, 151], "q": [60, 12, 243], "r": [83, 127, 88], "s": [147, 113, 118], "t": [57, 227, 1], "u": [221, 55, 160], "v": [247, 145, 80], "w": [113, 183, 245], "x": [171, 44, 192], "y": [10, 243, 128], "z": [86, 98, 254], "A": [125, 154, 204], "B": [200, 167, 231], "C": [72, 59, 200], "D": [70, 40, 251], "E": [145, 216, 239], "F": [83, 244, 150], "G": [22, 8, 100], "H": [131, 222, 67], "I": [220, 39, 54], "J": [60, 105, 241], "K": [245, 199, 217], "L": [171, 107, 112], "M": [20, 53, 163], "N": [106, 143, 125], "O": [150, 107, 143], "P": [11, 229, 148], "Q": [24, 68, 10], "R": [10, 89, 183], "S": [14, 120, 179], "T": [165, 142, 207], "U": [22, 110, 126], "V": [113, 209, 59], "W": [97, 247, 240], "X": [77, 141, 214], "Y": [252, 76, 234], "Z": [112, 178, 239], "0": [175, 221, 64], "1": [218, 17, 17], "2": [101, 10, 169], "3": [78, 36, 157], "4": [13, 65, 65], "5": [53, 74, 38], "6": [58, 229, 246], "7": [78, 143, 237], "8": [242, 169, 185], "9": [157, 135, 174], "!": [204, 253, 180], "\"": [19, 53, 178], "#": [211, 128, 147], "$": [224, 135, 219], "%": [143, 157, 146], "&": [4, 230, 78], "'": [63, 6, 226], "(": [84, 3, 157], ")": [232, 204, 249], "*": [52, 101, 113], "+": [50, 50, 2], ",": [197, 155, 254], "-": [205, 220, 146], ".": [71, 239, 219], "/": [72, 126, 99], ":": [74, 211, 147], ";": [149, 170, 140], "<": [249, 90, 84], "=": [94, 63, 137], ">": [151, 170, 6], "?": [254, 112, 232], "@": [51, 185, 164], "[": [25, 178, 115], "\\": [169, 196, 174], "]": [133, 228, 101], "^": [30, 138, 142], "_": [181, 248, 155], "`": [167, 19, 227], "{": [226, 111, 125], "|": [90, 68, 34], "}": [238, 74, 201], "~": [113, 244, 45]}

[Sirius3]

Bei einem Set wirst Du auch keine Doppelten Einträge finden, weil ja jeder Key einzigartig ist.
Du kannst aber die Values als Tuple in ein Set packen.

[Fire Spike]

Ok aber wieso gibt es einen Fehler?

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json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Json Datei

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{"a": [95, 250, 200], "b": [18, 139, 158], "c": [194, 147, 94], "d": [108, 1, 242], "e": [186, 127, 130], "f": [47, 3, 5], "g": [140, 120, 222], "h": [162, 70, 192], "i": [82, 164, 106], "j": [19, 204, 48], "k": [19, 202, 172], "l": [201, 10, 151], "m": [30, 160, 185], "n": [49, 75, 120], "o": [22, 113, 236], "p": [60, 234, 231], "q": [43, 234, 170], "r": [243, 180, 86], "s": [50, 65, 49], "t": [251, 71, 103], "u": [10, 20, 191], "v": [140, 220, 242], "w": [153, 202, 66], "x": [212, 176, 30], "y": [84, 64, 161], "z": [179, 2, 58], "A": [152, 193, 13], "B": [240, 196, 237], "C": [214, 189, 33], "D": [33, 133, 74], "E": [121, 127, 213], "F": [106, 139, 220], "G": [232, 32, 211], "H": [128, 99, 161], "I": [204, 16, 173], "J": [236, 115, 175], "K": [103, 40, 178], "L": [170, 249, 217], "M": [199, 161, 144], "N": [147, 36, 14], "O": [132, 154, 232], "P": [29, 46, 203], "Q": [140, 54, 208], "R": [189, 15, 236], "S": [68, 10, 230], "T": [35, 69, 160], "U": [196, 165, 101], "V": [148, 214, 13], "W": [214, 14, 4], "X": [140, 187, 189], "Y": [221, 46, 70], "Z": [137, 93, 128], "0": [12, 200, 57], "1": [212, 95, 135], "2": [139, 104, 26], "3": [88, 222, 80], "4": [236, 18, 5], "5": [233, 245, 3], "6": [244, 244, 213], "7": [147, 216, 28], "8": [115, 202, 202], "9": [163, 60, 234], "!": [144, 83, 219], "\"": [83, 37, 224], "#": [173, 102, 21], "$": [120, 206, 220], "%": [18, 16, 118], "&": [63, 88, 75], "'": [50, 2, 88], "(": [55, 59, 146], ")": [96, 238, 254], "*": [198, 153, 146], "+": [69, 68, 103], ",": [185, 221, 106], "-": [170, 55, 153], ".": [227, 143, 157], "/": [53, 174, 238], ":": [104, 226, 110], ";": [233, 210, 245], "<": [124, 26, 93], "=": [112, 40, 201], ">": [196, 152, 59], "?": [140, 246, 40], "@": [51, 26, 29], "[": [115, 156, 237], "\\": [29, 33, 150], "]": [23, 189, 88], "^": [151, 179, 235], "_": [158, 251, 45], "`": [82, 134, 84], "{": [163, 173, 19], "|": [186, 34, 70], "}": [172, 4, 213], "~": [86, 239, 85]}

Code

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def zgü():
    s = set()
    with open("aaa") as f:
        for i in json.load(f).values():
            s.add(tuple(i))
        if len(json.load(f).values()) != len(s):
            print("doppelte werte")
    print(s)

[__blackjack__]

@Fire Spike: Wenn Du etwas aus einer offenen Datei liest, dann ist danach der Dateizeiger hinter den gelesenen Daten. Die kann man also nicht einfach wieder lesen ohne den Dateizeiger wieder an den Anfang der Daten zu setzen. Wobei es aber sowieso nicht wirklich schlau ist die Datei zwei mal zu lesen wenn man das auch *einmal* machen könnte.