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editing batch filenames
Verfasst: Freitag 23. Juni 2006, 21:33
von drpython
please forgive my lack of Deutsche, but I don't know where else to ask for help.
I have several files with file names that look like this:
mas.4.res.120
mas.4.res.124
mas.4.res.122
mas.4.res.128
mas.4.res.129
I need to extract the last three numbers and print it to a file.
Please help me with either python or awk
thanks again
Verfasst: Freitag 23. Juni 2006, 22:26
von BlackJack
Just split the names at the dots and use the last element:
Code: Alles auswählen
In [14]:filenames = ['mas.4.res.120', 'mas.4.res.124', 'mas.4.res.122']
In [15]:for filename in filenames:
.15.: print filename.split('.')[-1]
.15.:
120
124
122
Verfasst: Freitag 23. Juni 2006, 22:28
von drpython
danke!
can I replace
with
?
Verfasst: Freitag 23. Juni 2006, 22:43
von gerold
drpython hat geschrieben:can I replace
with
Hi drpython!
I think, the simplest way is, to use "glob". Here´s an example:
Code: Alles auswählen
import glob
filelist = glob.glob("./mas*")
for filename in filelist:
print filename.split(".")[-1]
Regards,
Gerold
Verfasst: Freitag 23. Juni 2006, 22:58
von drpython
is filename a variable? forgive me, I'm VERY new to python.
Verfasst: Freitag 23. Juni 2006, 23:57
von Python 47
drpython hat geschrieben:is filename a variable? forgive me, I'm VERY new to python.
Hi drpython
Yes it is a variable. How can i explain it to you?
ok a simple example:
So x becomes the value of each number. So in the first Run x=1, in the secound Run x=2 and so on. I hope you unterstand my little example.
But I think
here
and
here (7.3) it is besser explained.
Verfasst: Samstag 24. Juni 2006, 01:11
von drpython
no, that was a great explanation! thanks again!!!
I tried to run my Python code and there was something wrong...infinite loop I think...I must have typed something wrong...so I'll check tomorrow
thanks again !
Dankeshun...i think?